How to add vertors

To determine the resultant : As we add straight vectors (※subtracting vectors means adding a vector in the opposite direction) , we would find the closest distance between the origin and destination. That would be our resultant. According to the Pythagorean Theorem, a² + b² = c², which "c" represents the hypoteneuse.

To determine the angle : The easiest way to measure the angle accordance to N or S is to use the protactor. But in this course, we would recommand to use the Trigonometry Theorem, Cos, Sin and Tan.

 To determine the vectors components: First, we set the positive axes, then break all vectors down into two components ( x and y). We calculate the total of x and y and follow the step as above (To determine the resultant, To determine the angle )

How equation#4 derived from the V/T graph

In Equation #4, only V2 is usable. In another way to calculate the area of the trapezoid, we could calculate the area of the trangle and subtract the area of the triangle.   That would come out the equation #4, which is d=V2Δt-½aΔt².

Equation #4  ────  d=V2Δt - ½aΔt²
                                   ↓            ↓
                              Rectangle    Triangle


To determine the area of the rectangle, we would multiple V2 (as symbol "b" shown in the graph《Height》)  to t2 - t1, which known as Δt. (as symbol "h" shown in the graph《Height》)

It will give us an equation,
Area of Rectangle = V2Δt

To determine the area of the rectangle, we would multiple (V2 - V1) 《Base》to  Δt 《Height》divided by 2.

According to Equation #1  = V2 - V1, so, as we sub this equation,
                                         V1= V2 -  aΔt

Area of triangle = ½(V2 - V1)(Δt)
Area of triangle = ½(V2 - V2 - aΔt)Δt
Area of triangle = ½(- aΔt)Δt
Area of triangle = -½aΔt²

Displacement = Area of rectangle - Area of triangle (As we sub the equations in,)

Displacement = V2t + ( -½aΔt²)

Displacement = V2t - ½aΔt²

How equation #3 translates into the v/t graph

                               
Equation #3  ────   d = V1Δt + 1/2 aΔt²
                                          ↓             ↓
                                   rectangle   triangle

As the graph above, we know that we have to calculate the area of the trapezoid to find out the displacement. But, in Equation #3, only V1 is usable. We would break down the trapezoid into a triangle and rectangle.

To determine the area of the rectangle, we would multiple V1 (as symbol "a" shown in the graph《Width》) to t2 - t1, which known as Δt. (as symbol "h" shown in the graph《Height》)

It will give us a equation of  Area of rectangle = V1Δt

To determine the area of the triangle, we would multiple (V2 - V1) 《Base》to  Δt 《Height》divided by 2

According to Equation #1 aΔt = V2 - V1, so, as we sub this equation,
Area of triangle = ½(V2 - V1)(Δt)
Area of triangle = ½aΔt(Δt)
                        
Displacement = Total Area

Displacement = Area of rectangle + Area of triangle  (As we sub the equations in,)

Displacement = ½V1Δt + aΔt²
                                      

Translation of Graph

Graph B)
There are five sections in this graph:

Velocity →↓
Section 1) Time (in second) 0 ~ 1  : The Velocity starts at the x-axis, a horizontal line which lies on the x-axis is created.
Section 2) Time (in second) 1 ~ 3  : A horizontal line is created in the positive area at  0.75 as the walking speed is 0.75m/s [E]     Slope: 1.5(m)/2(s)
Section 3) Time (in second) 3 ~ 6  : No change in distance, so there's a horizontal line on the x-axis.
Section 4) Time (in seond) 6 ~ 7.5  : A horizontal line is created in the negative area at -0.53 as the walking speed is 0.53m/s [W]c or -0.53m/s [E]    Slope: -0.8(m)/1.5(s)
Section 5) Time (in second) 7.5 ~ 10  : No change in distance, so there's a horizontal line on the x-axis.

Acceleration →↓
 There's no acceleration in this graph. The line lies on the x-axis.

Graph C)
There are 5 sections in this graph
Velocity →↓
Section 1) Time (in second) 0 ~ 3  : A horizontal line is created in the negative area at -0.5 as the walking speed is 0.5m/s [W] or -0.5m/s[E]   Slope: -1.5(m)/3(s)
Section 2) Time (in second) 3 ~ 4  : No change in distance, so there's a horizontal line on the x-axis.
Section 3) Time (in second) 4 ~ 5  : A horizontal line is created in the negative area at 1 as the walking speed is 1m/s [W] or -1m/s [E]    Slope: -1(m)/1(s)
Section 4) Time (in second) 5 ~ 7  : No change in distance, so there's a horizontal line on the x-axis.
Section 5) Time (in second) 7 ~ 10  : A horizontal line is created in the positive area at 0.83 as the walking speed is 0.83m/s    Slope: 2.5(m)/3(s)

Acceleration →↓
There's no accelerationin this graph. The line lies on the x-axis.


Graph D)
There are 4 sections is this graph:

Distance →↓
Section 1) Time (in second) 0 ~ 2  : The distance start from 0m, and stay for 2 seconds therefore a horizontal line lies on the x-axis.
Section 2) Time (in second) 2 ~ 5  : The line goes up with a positive direction and stop at 1.5m away the origin.  Distance: 0.5(m/s)*3(s)
Section 3) Time (in second) 5 ~ 7  : The velocity is 0, that causes a horizontal line is drawn at 1.5m.
Section 4) Time (in second) 7 ~10  : The line decreases with a negative direction and stop at 0. Distance : -0.5(m/s)*3(s)
Acceleration →↓There's no acceleration in this graph. The line lies on the x-axis.


Graph E)
There are 4 sections in this graph:

Distance →↓
Section 1)
 Time (in second) 1 ~ 4  : The speed increases in a speed of 0.125m/s Slope: 0.5(m/s)/4(s), so it will become a curve, a cureve which has a smaller slope at first and become gather and the line stop at 1m away the origin.
Section 2) Time (in second) 4 ~ 6  : The line goes up with a positive direction and stop at 2m away the origin.   Distance: 0.5(m/s)*2(s)
Section 3) Time (in second) 6 ~ 9  : The line decreases with a negative direction and stop at 0.8m away thre origin.  Distance: -0.4(m/s)*3(s)
Section 4) Time (in second) 9 ~ 10  : The velocity is 0, that causes a horizontal line is drawn at 0.8m

Acceleration →↓Section 1) Time (in second) 1 ~ 4  : A horizontal line is created at 0.125(m/s2) Slope: 0.5(m/s)/4(s).
Section 2 ~ 4) There're no acceleration in section 2 to 4. The line from 4 to 10 second is on the x-axis.

Graph F)
There are 3 sections in this graph:

Velocity →↓
Section 1) Time (in second) 1 ~ 4  : A horizontal line is created in the positive area at 0.26m as the walking speed is 0.26m/s  Slope: 0.9(m)/3.5(s)
Section 2) Time (in second) 4 ~ 6.5  : No change in the distance, so there's a horizontal line on the x-axis.
Section 3) Time (in second) 6.5 ~ 10  : A horizontal line is created in the positive area at 0.43 as the walking speed is 0.43m/s  Slope: 1.5(m)/3.5(s)
Acceleration →↓There's no acceleration in this graph. The line lies on the x-axis.

Motion prelab

Distance (m) VS. Time (s)

1. Stay at 1m away from the origin for 1 second.

2. Walk 1.5m in 2 seconds away from the origin. [0.75m/s]

3. Stay at 2.5m away the origin for 3 seconds.

4. Walk 0.75m in 1.5 seconds towards the origin. [0.5m/s]
5. Stay at  1.75m away teh origin for 2.5 s.

                                             Distance (m) VS. Time (s)

1. Start from 3m away the origin, walk 1.5m for 3s towards the origin. [0.5 m/s]

2. Stay at 1.5m away the origin for 1 s.

3. Run 1m in 1 second toward the origin. [1 m/s]

4. Stay at  0.5m away the origin for 2 s.

5. Run 2.5m away the origin in 3 seconds. [0.83 m/s]

                                Velocity

1. Stay for 2 seconds.
2. Walk at 0.5 m/s away the origin for 3 seconds.
3. Stay for 2 seconds.
4. Walk at 0.5 m/s toward the origin for 3 seconds.








                                                                                  Velocity

 

1. Speeds up  to 0.5 m/s away the origin in 4 seconds.

2. Walk in constant speed [0.5m/s] away the origin for 2 seconds.

3. Walk at [0.4 m/s] towards the origin  for 3 seconds.

4. Stop walking and stay for 1 second.



                    Distance (m) VS. Time (s)

1. Start from 0.9m away the origin, walk  0.9m away the away in 3.5 s [0.26 m/s]

2. Stay at 1.8m away the origin for 3 s.

3. Walk 1.5m away the origin in 3.5 s (0.43 m/s)







                                                                                        Velocity

1. Walk  at 0.35 m/s away the origin for 3 seconds.

2. Walk at 0.35 m/s toward the origin for 3.5 seconds.

3. Stand  for 3.5 seconds.

MOTOR PRINCIPLE

 1.     In this motor model, the power (conventional
current flow) flow though the brushes and connect to
the commutator pin. It causes it to become a DC motor.
According to the RHR #2, the direction of conventional
current flow is shown in the picture which located at the
middle. After using the RHR #2, we could predict the
direction of the force by using the RHR #3. The direction
of the force at the left side is different from the right
side’s, so the cork could spin.

.

 2.     Then, after the motor spins half way of a circle, the
commutator pins touched another brush (not the brush
 that has been touched before the motor spins) that
changed the direction if the current and also the direction
of forces changed, too.

 
3.     After the forces changed when the motor reached
the half way point, the motor continues to spin and
it changed its forces while it meets another half way
point, and it spins more and more that forms a loop.

 

Now， the loop has been formed and the cork can spin
nicely until there is no power anymore.